题解来喽!
2025-05-25 09:15:21
发布于:浙江
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N = int(input())
for _ in range(N):
num_str = input()
is_binary = 1
is_octal = 1
is_decimal = 1
is_hexadecimal = 1
for char in num_str:
if char not in '01':
is_binary = 0
break
for char in num_str:
if not ('0' <= char <= '7'):
is_octal = 0
break
for char in num_str:
if not ('0' <= char <= '9'):
is_decimal = 0
break
for char in num_str:
if not (('0' <= char <= '9') or ('A' <= char <= 'F')):
is_hexadecimal = 0
break
print(f"{is_binary} {is_octal} {is_decimal} {is_hexadecimal}")
这里空空如也
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