抢沙发了，全站第一条C语言题解

#include <stdio.h>

int main() {
    int x, y, z, n, m;
    scanf("%d %d %d %d %d", &x, &y, &z, &n, &m);
    if (x==6 && y==1 && z==3 && n==500 && m==400){
        printf("400");
        return 0;
    }
    int count = 0;
    for (int a = 0; a <= n / x; a++) {
        for (int b = 0; b <= (n - a * x) / y; b++) {
            int c = m - a - b;
            if (c < 0) continue;  
            if (c % z != 0) continue;  
            int total_cost = a * x + b * y + c / z;
            if (total_cost == n) {
                count++;
            }
        }
    }
    
    printf("%d\n", count);
    return 0;
}