自定义函数解法

既然放在自定义函数里面，那就自定义函数做呗

#include<bits/stdc++.h>
using namespace std;
double f(int s, int t1, int t2) {
    const double pi = 3.14;
    double x = (double)s / t1;
    double y = x * t2;
    double r = cbrt(3.0 * y / (4.0 * pi));
    return r;
}
int main(){
    int s, t1, t2;
    if (cin >> s >> t1 >> t2) {
        double radius = f(s, t1, t2);
        cout << fixed << setprecision(2) << radius << endl;
    }
    
    return 0;
}