题解

#include <bits/stdc++.h>
using namespace std;
int A[1005][1005];
int main(){
	int n,m,cnt = 0;
	cin >> n >> m;
	for(int i = 1;i<= n;i++){
		for(int j = 1;j <= n;j++){
			cin >> A[i][j];
			if(A[i][j] % m == 0){
				cnt++;
			}
		}
	}
	cout << cnt;
	return 0;
}