欢乐赛#37T6

首先读取输入，将每个灯被按下的次数存储在一个二维数组 b 中。所有灯初始状态为开启（即 a[i][j] = 1）。对于每个灯，根据其被按下的次数进行状态切换。每次按下一个灯，该灯及其上下左右相邻的灯都会切换状态。最后输出每个灯的最终状态

#include <bits/stdc++.h>
using namespace std;
bool a[5][5];
int b[5][5];
int main(){
    for (int i = 1;i <= 3;i++){
        for (int j = 1;j <= 3;j++){
            cin >> b[i][j];
        }
    }
    for (int i = 1;i <= 3;i++){
        for (int j = 1;j <= 3;j++){
            a[i][j] = 1;
        }
    }
    for (int i = 1;i <= 3;i++){
        for (int j = 1;j <= 3;j++){
            while(b[i][j]--){
                a[i][j] = !a[i][j];
                a[i + 1][j] = !a[i + 1][j];
                a[i - 1][j] = !a[i - 1][j];
                a[i][j + 1] = !a[i][j + 1];
                a[i][j - 1] = !a[i][j - 1];
            }
        }
    }
    for (int i = 1;i <= 3;i++){
        for (int j = 1;j <= 3;j++){
            cout << a[i][j];
        }
        cout << endl;
    }
    return 0;
}