题解

#include <iostream>
using namespace std;
// 计算C(x, 2) = x * (x - 1) / 2
int choose2(int x) {
    return x * (x - 1) / 2;
}
int main() {
    int n, m;
    scanf("%d%d",&n,&m) ;
    int square = 0;
    int minn = min(n, m);
    for (int k = 1; k <= minn; k++) {
        square += (n - k + 1) * (m - k + 1);
    }
    // 计算长方形的总数
    int totalRectangles = choose2(n + 1) * choose2(m + 1);
    // 长方形的个数 = 总长方形数 - 正方形的个数
    int rectangle = totalRectangles - square;
    printf("%d %d\n",square,rectangle) ;
    return 0;
}