A31009.【循环】【提高】数字反转

#include<iostream>
using namespace std;
int backint(int a);
int main(){
	int n;
    cin>>n;
    cout<<backint(n);
	return 0;
} 
int backint(int a){
	int back=0;
	while(a){
		back=back*10+a%10;
		a/=10;
	}
	return back;
}