简单

//这题其实很简单，就是加了个结构体
#include<bits/stdc++.h>
using namespace std;
struct jiang
{
    string name;    
    int jin;
    int yin;
    int tong;
    int zong;
};
int main()
{
    int n;
    jiang a[105];
    cin>>n;
    for(int i = 1;i<=n;i++)
    {
        cin>>a[i].name>>a[i].jin>>a[i].yin>>a[i].tong;
        a[i].zong = a[i].jin+a[i].yin+a[i].tong;//总奖牌数
    }
    for(int i = 1;i<=n;i++)
    {
        cout<<a[i].name<<" "<<a[i].jin<<" "<<a[i].yin<<" "<<a[i].tong<<" "<<a[i].zong<<endl;//输出
    }    
}

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