解法如下：

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int d;
cin>>d;
int a=d/100,b=(d-a100)/10,c=(d-a100-b10);
if(pow(a,3)+pow(b,3)+pow(c,3)==a100+b*10+c)
{
cout<<"YES";
}
else
{
cout<<"NO";
}
}