一种很新的解法(?)

#include<iostream>
using namespace std;
int main(){
    char A,B,C;
    int a,b,c;
    cin>>A>>B>>C;
    a=int(A)-'0';
    b=int(B)-'0';
    c=int(C)-'0';
    if(a*a*a+b*b*b+c*c*c==100*a+10*b+c)cout<<"YES";
    else cout<<"NO";
    return 0;
}