标准题解

#include<iostream>
#include<cmath>
int n;
int main(){
	scanf("%d",&n);
	int a,b,c;
	a = n / 100;
	c = n % 10;
	b = (n - a * 100 - c) / 10;
	int sum = pow(a,3) + pow(b,3) + pow(c,3);
	if(sum == n) printf("YES");
	else printf("NO");
	return 0;
}