题解 | A30691.求奇偶数之和

#include <bits/stdc++.h>
using namespace std;
int n , a[5010];
int s1 , s2;
int main(){
	cin >> n;
    for(int i = 1;i <= n;i++){
        cin >> a[i];
    }
    for(int i = 1;i <= n;i++){
        if(a[i]%2 != 0){ //判断是否为奇数
            s1 += a[i];
        }
        else{
            s2 += a[i];
        }
    }
    cout << s1 << "\n" << s2;
    return 0;
}