for循环嵌套

#include<bits/stdc++.h>
using namespace std;
int main() {
int n,i;
cin >> n;
for ( i = 1; i <= n; i ){
for (int j = 1; j <= (n+1)/2+abs(i-(n+1)/2); j)//计算每行输入的次数
if(j<=(n+1)/2-1-abs(i-(n+1)/2))//计算每行空格的长度
cout << ' ';
else
cout << '*';
cout << '\n';
}
return 0;
}