数位分离

题解

#include<bits/stdc++.h>
using namespace std;
using ll = long long; 
int main(){
	ll n,a=0,b=0,c=0,d=0;
	cin>>n;
	a=n/1%10;
	b=n/10%10;
	c=n/100%10;
	d=n/1000%10;
	if((pow(a,4)+pow(b,4)+pow(c,4)+pow(d,4))!=n){
		cout<<"No";
	}else{
		cout<<"Yes";
	}
	return 0;
}