全部评论 1

  • #include<bits/stdc++.h>
    using namespace std;

    string f(long long num)
    {
    string s="";
    while (num>0)
    {
    if (num%26==0)
    {
    s='Z'+s;
    num=(num-1)/26;
    }
    else
    {
    s=(char)('A'+num%26-1)+s;
    num/=26;
    }
    }
    return s;
    }

    int main()
    {
    long long n;
    cin >> n;
    cout << f(n) << endl;
    return 0;
    }

    2025-03-22 来自 四川

    0
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