背景：

原题链接
就我一个人是写正解的吗（只统计对的）？其他显示“已通过”的人都是输出样例的吗？虽然过于复杂
有大佬能给点意见和更好的思路吗？

思路：

分别模拟上半部分和下半部分每一行输出空格数和输出$X$的位置，用合适的变量统计输出空格数和$X$数。

代码（懒得写注释了）：

#include <iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    while (n--){
        int a,b;
        cin>>a>>b;
        int f=0,l=a-2,f2=0;
        for (int i=1;i<=a/2;i++){
            for (int j=1;j<=f;j++){
                cout<<" ";
            }
            f++;
            cout<<"X";
            for (int i=1;i<=l;i++){
                cout<<" ";
            }   
            l-=2;
            cout<<"X";
            for (int j=1;j<=f2;j++){
                cout<<" ";
            }
            f2++;
            cout<<endl;
        }
        for (int i=1;i<=a/2;i++){
            cout<<" ";
        }
        cout<<"X";
        for (int i=1;i<=a/2;i++){
            cout<<" ";
        }
        cout<<endl;
        f=a/2-1,l=1,f2=a/2-1;
        for (int i=1;i<=a/2;i++){
            for (int j=1;j<=f;j++){
                cout<<" ";
            }
            f--;
            cout<<"X";
            for (int i=1;i<=l;i++){
                cout<<" ";
            }   
            l+=2;
            cout<<"X";
            for (int j=1;j<=f2;j++){
                cout<<" ";
            }
            f2--;
            cout<<endl;
        }
        for (int i=1;i<b;i++){
            int f=1,l=a-4,f2=1;
            for (int i=1;i<=a/2-1;i++){
                for (int j=1;j<=f;j++){
                    cout<<" ";
                }
                f++;
                cout<<"X";
                for (int i=1;i<=l;i++){
                    cout<<" ";
                }   
                l-=2;
                cout<<"X";
                for (int j=1;j<=f2;j++){
                    cout<<" ";
                }
                f2++;
                cout<<endl;
            }
            for (int i=1;i<=a/2;i++){
                cout<<" ";
            }
            cout<<"X";
            for (int i=1;i<=a/2;i++){
                cout<<" ";
            }
            cout<<endl;
            f=a/2-1,l=1,f2=a/2-1;
            for (int i=1;i<=a/2;i++){
                for (int j=1;j<=f;j++){
                    cout<<" ";
                }
                f--;
                cout<<"X";
                for (int i=1;i<=l;i++){
                    cout<<" ";
                }   
                l+=2;
                cout<<"X";
                for (int j=1;j<=f2;j++){
                    cout<<" ";
                }
                f2--;
                cout<<endl;
            }
        }
        cout<<endl;
    }
    return 0;
}

希望对大家学习OI有帮助！