全网首发 | 解密(decode) |

#include <iostream>
#include <cmath>
typedef long long K;
int main() {
    int k;
    std::cin >> k;
    for (int i = 0; i < k; ++i) {
        K n, d, e;
        std::cin >> n >> d >> e;
        K m = n - e * d + 2;
        K delta = m * m - 4 * n;
        K sqrt_delta = static_cast<K>(std::sqrt(delta));
        if (delta < 0 || sqrt_delta * sqrt_delta != delta) {
            std::cout << "NO" << std::endl;
        } else {
            K p = (m - sqrt_delta) / 2;
            K q = (m + sqrt_delta) / 2;
            std::cout << p << " " << q << std::endl;
        }
    }

    return 0;
}