题解

#include <iostream>
#include <cstdio>

int main() {
    int n;
    if (!(std::cin >> n)) return 0;
    
    int base_total, base_effective;
    std::cin >> base_total >> base_effective;
    
    // 计算基准有效率（鸡尾酒疗法）
    double base_rate = (double)base_effective / base_total;
    
    // 处理剩下的 n-1 组改进疗法
    for (int i = 1; i < n; ++i) {
        int total, effective;
        std::cin >> total >> effective;
        
        // 计算当前改进疗法的有效率
        double current_rate = (double)effective / total;
        
        // 根据差值判断效果
        if (current_rate - base_rate > 0.05) {
            std::cout << "better" << std::endl;
        } else if (base_rate - current_rate > 0.05) {
            std::cout << "worse" << std::endl;
        } else {
            std::cout << "same" << std::endl;
        }
    }
    
    return 0;
}