必AC

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;//long long代替ll。
int a[100010],n,k;
int f(int m){
	int sum = 0;
	for(int i = 1;i <= n;i ++)sum += a[i] / m;
	return sum;
}
int main(){
	ios::sync_with_stdio(false);
	cin.tie(0);cout.tie(0);
	cin >> n >> k;
	for(int i =1;i <= n;i ++)cin >> a[i];
	int l = 1,r = 100000,mid,ans = 0;
	while (l <= r) {//二分答案过程
		mid = (l + r) / 2;
		if(f(mid) > k)l = mid + 1;
		else if(f(mid) == k)
        {
			ans = mid;
			l = mid + 1;
		}else r = mid - 1;
	}
	cout << ans;//输出
	return 0;
}

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