题解
2025-07-01 14:53:25
发布于:浙江
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#include <stdio.h>
#include <string.h>
int main() {
int n;
char original[100010];
scanf("%d", &n);
getchar();
fgets(original, 100010, stdin);
size_t len = strlen(original);
if (len > 0 && original[len - 1] == '\n') {
original[len - 1] = '\0';
}
for (int i = 0; original[i] != '\0'; i++) {
if (original[i] >= 'a' && original[i] <= 'z') {
original[i] = 'a' + (original[i] - 'a' + n) % 26;
}
}
printf("%s\n", original);
return 0;
}
这里空空如也
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