样例3

样例3输出应该是17

此题如果n%2==1,数列n的第k项为nk
输出=|1-n1|+|1-n2|+|1-n3|+.......+|1-nk|

#include<iostream>
using namespace std;
int abs(int x){
    if(x>=0){
        return x;
    }else{
        return -x;
	}
}
int main(){
    int n;
    cin >> n;
    int l[n];
    for(int i=0;i<n;i++){
        cin >> l[i];
    } 
    if(n%2==1){
        int c=0;
        for(int i=0;i<n;i++){
            c+=abs(1-l[i]);
        }
        cout << c;
    }
    if(n%2==0){
        int c1=0,c2=0;
        for(int i=0;i<n;i++){
            c1+=abs(1-l[i]);
            c2+=abs(1+l[i]);
        }
        if(c1>=c2){
            cout << c2;
        }else if(c1<=c2){
            cout << c1;
        }
    }
    return 0;
}