题解
2024-08-29 11:15:23
发布于:广东
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#include <bits/stdc++.h>
using namespace std;
const int N = 105;
char a[N][N];
int b[N][N];
int x[] = {-1,-1,-1,0,0,1,1,1};
int y[] = {-1,0,1,-1,1,-1,0,1};
int main(){
    int n , m;
    cin >> n >> m;
    for (int i = 1 ; i <= n ; i++){
    	for (int j = 1 ; j <= m ; j++){
        	cin >> a[i][j];
            if (a[i][j] == '*'){
            	for (int k = 0 ; k <= 7 ; k++) b[i + x[k]][j + y[k]]++;
            }
        }
    }
    for (int i = 1 ; i <= n ; i++){
    	for (int j = 1 ; j <= m ; j++){
        	if (a[i][j] == '*') cout << '*';
            else cout << b[i][j];
        }
        cout << endl;
    }
	return 0;
}
这里空空如也

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