题解

x是高位和低位的分隔线

#include <iostream>
#include <cstdio>
using namespace std;
int a[100005];
const unsigned x = 1 << 16;
int main(){
	unsigned n;
	cin >> n;
	unsigned n1 = n / x, n2 = n % x;
	cout << n2 * x + n1;//交换

	return 0;
}