AC题解
2025-08-09 19:13:17
发布于:广东
#include<bits/stdc++.h>
#define ll long long
#define ld long double
#define pint pair<ll,ll>
#define mk(x,y) make_pair(x,y)
#define fir first
#define sec second
#define Rep(x,y,z) for(ll x=y;x<=z;++x)
#define Red(x,y,z) for(ll x=y;x>=z;--x)
using namespace std;
char buf[1<<12],*p1=buf,p2=buf,nc;ll ny;
inline char gc(){return getchar();}
inline ll read(){
ll x=0;ny=1;while(nc=gc(),(nc<48||nc>57)&&nc!=EOF)if(nc==45)ny=-1;if(nc<0)return nc;
x=nc-48;while(nc=gc(),47<nc&&nc<58&&nc!=EOF)x=(x<<3)+(x<<1)+(nc^48);return xny;
}struct BigInteger {
typedef unsigned long long LL;
static const int BASE = 100000000;
static const int WIDTH = 8;
vector<int> s;
BigInteger& clean(){while(!s.back()&&s.size()>1)s.pop_back(); return *this;}
BigInteger(LL num = 0) {*this = num;}
BigInteger(string s) {*this = s;}
BigInteger& operator = (long long num) {
s.clear();
do {
s.push_back(num % BASE);
num /= BASE;
} while (num > 0);
return *this;
}
BigInteger& operator = (const string& str) {
s.clear();
int x, len = (str.length() - 1) / WIDTH + 1;
for (int i = 0; i < len; i++) {
int end = str.length() - i*WIDTH;
int start = max(0, end - WIDTH);
sscanf(str.substr(start,end-start).c_str(), "%d", &x);
s.push_back(x);
}
return (*this).clean();
}
BigInteger operator + (const BigInteger& b) const {
BigInteger c; c.s.clear();
for (int i = 0, g = 0; ; i++) {
if (g == 0 && i >= s.size() && i >= b.s.size()) break;
int x = g;
if (i < s.size()) x += s[i];
if (i < b.s.size()) x += b.s[i];
c.s.push_back(x % BASE);
g = x / BASE;
}
return c;
}
BigInteger operator - (const BigInteger& b) const {
assert(b <= *this);
BigInteger c; c.s.clear();
for (int i = 0, g = 0; ; i++) {
if (g == 0 && i >= s.size() && i >= b.s.size()) break;
int x = s[i] + g;
if (i < b.s.size()) x -= b.s[i];
if (x < 0) {g = -1; x += BASE;} else g = 0;
c.s.push_back(x);
}
return c.clean();
}
BigInteger operator * (const BigInteger& b) const {
int i, j; LL g;
vector<LL> v(s.size()+b.s.size(), 0);
BigInteger c; c.s.clear();
for(i=0;i<s.size();i++) for(j=0;j<b.s.size();j++) v[i+j]+=LL(s[i])*b.s[j];
for (i = 0, g = 0; ; i++) {
if (g ==0 && i >= v.size()) break;
LL x = v[i] + g;
c.s.push_back(x % BASE);
g = x / BASE;
}
return c.clean();
}
BigInteger operator / (const BigInteger& b) const {
assert(b > 0);
BigInteger c = *this;
BigInteger m;
for (int i = s.size()-1; i >= 0; i--) {
m = m*BASE + s[i];
c.s[i] = bsearch(b, m);
m -= b*c.s[i];
}
return c.clean();
}
BigInteger operator % (const BigInteger& b) const {
BigInteger c = *this;
BigInteger m;
for (int i = s.size()-1; i >= 0; i--) {
m = m*BASE + s[i];
c.s[i] = bsearch(b, m);
m -= b*c.s[i];
}
return m;
}
int bsearch(const BigInteger& b, const BigInteger& m) const{
int L = 0, R = BASE-1, x;
while (1) {
x = (L+R)>>1;
if (b*x<=m) {if (b*(x+1)>m) return x; else L = x;}
else R = x;
}
}
BigInteger& operator += (const BigInteger& b) {*this = *this + b; return *this;}
BigInteger& operator -= (const BigInteger& b) {*this = *this - b; return *this;}
BigInteger& operator *= (const BigInteger& b) {*this = *this * b; return *this;}
BigInteger& operator /= (const BigInteger& b) {*this = *this / b; return *this;}
BigInteger& operator %= (const BigInteger& b) {*this = *this % b; return *this;}
bool operator < (const BigInteger& b) const {
if (s.size() != b.s.size()) return s.size() < b.s.size();
for (int i = s.size()-1; i >= 0; i--)
if (s[i] != b.s[i]) return s[i] < b.s[i];
return false;
}
bool operator >(const BigInteger& b) const{return b < *this;}
bool operator<=(const BigInteger& b) const{return !(b < *this);}
bool operator>=(const BigInteger& b) const{return !(*this < b);}
bool operator!=(const BigInteger& b) const{return b < *this || *this < b;}
bool operator==(const BigInteger& b) const{return !(b < *this) && !(b > *this);}
};
ostream& operator << (ostream& out, const BigInteger& x) {
out << x.s.back();
for (int i = x.s.size()-2; i >= 0; i--) {
char buf[20];
sprintf(buf, "%08d", x.s[i]);
for (int j = 0; j < strlen(buf); j++) out << buf[j];
}
return out;
}
istream& operator >> (istream& in, BigInteger& x) {
string s;
if (!(in >> s)) return in;
x = s;
return in;
}
ll A2[70],A10[25],vis[1050],A30[60];
inline void pre(){
ll t=0;
Rep(i,1,1024){
vis[i]=(vis[i>>1]^(i&1));
if(vis[i])A2[t]=i;
}Rep(i,0,10)A10[i]=1<<i;Rep(i,12,16)A10[i]=1<<i-1;Rep(i,18,19)A10[i]=1<<i-2;
A10[11]=(1<<11)-1,A10[17]=(1<<16)-(1<<11)+(1<<6)-1;
Red(i,20,1)A10[i]=A10[i-1];A10[0]=0;
Rep(i,0,30)A30[i]=1<<i;Rep(i,32,46)A30[i]=1ll<<i-1;Rep(i,48,54)A30[i]=1ll<<i-2;
A30[31]=(1ll<<31)-1,A30[47]=(1ll<<46)-(1ll<<31)+(1<<16)-1;
Red(i,55,1)A30[i]=A30[i-1];A30[0]=0;
}ll n,k;
inline ll Get(){
ll x=read();
for(ll cnt=1;x;x/=k+1,cnt)if(x%(k+1)k)return cnt;
return 0;
}inline ll GetB(){
BigInteger x;cin>>x;
for(ll cnt=1;x!=0;x/=k+1,cnt++)if(x%(k+1)k)return cnt;
return 0;
}
inline void Solve1(){
ll tot=0;
Rep(i,1,n)tot^=read();
if(tot)puts("Preempt.");else puts("Leapfrog.");
}inline void Solve2(){
ll tot=0;
Rep(i,1,n)tot^=A2[Get()];
if(tot)puts("Preempt.");else puts("Leapfrog.");
}inline void Solve10(){
ll tot=0;
Rep(i,1,n)tot^=A10[Get()];
if(tot)puts("Preempt.");else puts("Leapfrog.");
}inline void Solve30(){
ll tot=0;
Rep(i,1,n)tot^=A30[GetB()];
if(tot)puts("Preempt.");else puts("Leapfrog.");
}
int main(){
pre();
for(ll t=read();t--;){
n=read(),k=read();
if(k1)Solve1();
else if(k2)Solve2();
else if(k10)Solve10();
else if(k30)Solve30();
}
return 0;
}
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