月落乌啼算钱（兔子数列）题解

#include <bits/stdc++.h>
using namespace std;
int main(){
    int n,f[n + 1];
    cin >> n;
    f[1] = f[2] = 1;
    for(int i = 3;i <= n;i ++){
        f[i] = f[i - 1] + f[i - 2];
    }
    cout << f[n] << ".00" << endl;
    return 0;
}