爱坤解题

#include <iostream>
using namespace std;
int chang, tiao, rap;
string ikun; 
int main(){
	cin >> ikun;
	int nitaimei = ikun.size();
	for (int ji = 0; ji < nitaimei; ji++){
		if (ikun[ji] == 'c'){
			chang++;
		}
		else if (ikun[ji] == 'p'){
			tiao++;
		}
		else if (ikun[ji] == 'd'){
			rap++;
		}
	}
	int basketball = 10000;
	if (chang < basketball) basketball = chang;
	if (tiao < basketball) basketball = tiao;
	if (rap/2 < basketball) basketball = rap/2;
	cout << basketball;
	return 0;
}