按我的写，保你拿到时空双修者 名额限一位

执行用时：2ms
内存消耗：1.39MB
击败了100.00%的用户
击败了100.00%的用户

#include <unistd.h>

static char inBuf[1 << 10];
static int inLen = 0, inPos = 0;

inline int readChar() {
if (inPos == inLen) {
inLen = read(0, inBuf, sizeof(inBuf));
inPos = 0;
if (inLen <= 0) return -1;
}
return inBuf[inPos++];
}

inline int readInt() {
int c = readChar();
while (c <= ' ') { if (c == -1) return -1; c = readChar(); }
int x = 0;
while (c > ' ') { x = x * 10 + (c - '0'); c = readChar(); }
return x;
}

static int a[305], b[305];

int main() {
int T = readInt();
while (T--) {
int n = readInt();
for (int i = 0; i < n; i++) a[i] = readInt();

    int left = 0, right = n - 1;
    for (int i = 0; i < n; i++) {
        if (i % 2 == 0) b[i] = a[left++];
        else b[i] = a[right--];
    }

    char out[4096];
    int len = 0;
    for (int i = 0; i < n; i++) {
        int v = b[i];
        if (v == 0) out[len++] = '0';
        else {
            char tmp[12]; int tl = 0;
            while (v) { tmp[tl++] = '0' + v % 10; v /= 10; }
            while (tl) out[len++] = tmp[--tl];
        }
        out[len++] = ' ';
    }
    out[len++] = '\n';
    write(1, out, len);
}
return 0;

}