题解

#include<bits/stdc++.h>
using namespace std;
int n, m, a[105][105], b[105][105];
int main() {
	cin>>n>>m;
	for (int i = 1; i <= n; ++i) {for (int j = 1; j <= m; j++) {cin>>a[i][j];}}
	for (int i = 1; i <= n; ++i) {for (int j = 1; j <= m; j++) {cin>>b[i][j];cout<<~(a[i][j]^b[i][j])<<" ";}cout<<endl;}
}
}