A143536.HZHS皓仔和水（题解）

#include<iostream>
using namespace std;
int main(){
int t;
cin >> t;
if(t < 0){
cout << "固体";
}
if(t == 0){
cout << "固液共存";
}
if(t > 0 && t < 100){
cout << "液体";
}
if(t == 100){
cout << "液气共存";
}
if(t > 100){
cout << "气体";
}
return 0;
}