Python解法
2025-03-29 20:38:25
发布于:上海
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def check_prime(n):
if n == 2:
return True
if n==0 or n==1:
return False
else:
for i in range(2,n):
if n%i == 0:
return False
return True
letters = []
letter_number = []
word = input()
for i in list(word):
if i not in letters:
letters.append(i)
letter_number.append(1)
elif i in letters:
letter_number[letters.index(i)] += 1
maxn = max(letter_number)
minn = min(letter_number)
if check_prime(maxn-minn):
print("Lucky Word")
print(maxn-minn)
else:
print("No Answer")
print("0")
这里空空如也
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