循环不一定要开long long

#include <bits/stdc++.h>
using namespace std;
long long n,cnt;
int main(){
    cin >> n;
    if (n==1) {cout << 1;return 0;}
    for (int i=0;pow(2,i)<=n;i++){
        cnt++;
    }
    cnt--;
    cout << cnt << endl;
    for (int i=0;i<cnt;i++){
        cout << (long long)(pow(2,i)) << "\n";
    }
}