“****，又输了，我直接拿那个筷子粘水泥就塞这个凋零风暴嘴里”随着第2^5次倒在了地上，锐脸已通红。 转头一看，入机损友响竟然一刀秒了凋零风暴，把风暴头（≈入头）抢了，他气得半死，把电脑暴击至死党枫手中，但他没有看到一个零件，却看见一个血红的按钮飞出，叫到：“你要参加这场游戏吗？”耳畔响起响的叫声：“零件一地，你还不捡，待会儿不帮你捡了……”，锐清醒过来，看见那个按钮，俨然是用零件组成的，却毫无瑕疵，似乎已经昭告了这场游戏，没有人是MVP…… 加团抢先看下一章哦~ 目录

作者新作死亡方块已开更！！ 加个团呗，可以提前2-3天在首页看到最新的一章 预告 序章 第一章已开始撰写……

我的团队《新手团》 https://www.acgo.cn/application/1941403203286142976

弟兄们！想不想做[未来之星]！加入我们吧！https://www.acgo.cn/application/1931215322856759296

一个一个定义： char s[6]={'w','o','r','l','d'}; 下标 0 1 2 3 4 5 内容 w o r l d 并且后面求长度时求不到。 用字符串定义： char s[6]="world"; 下标 0 1 2 3 4 5 内容 w o r l d \0 （会占位置，但取到的是空） 用cin可以直接输入，但遇到空格会停止 fgets(数组名,数组大小,stdin)整行输入 strlen(数组名)可以获得有效长度 strcat(字符串名1,字符串名2)将字符串2连接到字符串1后面 strcpy(字符串名1,字符串名2)将字符串2赋值给字符串1 strcmp(字符串名1,字符串名2)比较字符串1,字符串2，若字符串名1>字符串名2,返回正数，若字符串名1<字符串名2返回负数，否则返回0

链接描述 我怎么做都2个RE,望大佬们帮我优化. RE代码

1号夏老师：49 userId_undefined 谁来教我C++ 荣耀黄金 1336 2号夏老师：58 userId_undefined 谁来教我C++ 荣耀黄金 1299 49说58是假的！！！ 58只说loveacgo 到底谁真谁假呢？？？ 你知道吗？？？ 答案！！！： 据采访，58是真的夏老师！！！ 快告诉大家别认错人！！！

florr.io 讨论 心得 问题 都可以来分享！！！

为什么我用的Python，输出会变成这样？本喵不解，本喵无语

#include<iostream> using namespace std; int a[40]; int b[40]; int c[40]; int main(){ int n,sum=0,s=0; cin>>n; for(int i=1;i<=n;i++){ cin>>a[i]; } for(int i=1;i<=n;i++){ if(a[i]%2==0){ b[i]=a[i]; sum++; }else{ c[i]=a[i]; s++; } } for(int i=1;i<=sum;i++){ cout<<b[i]<<" "; } cout<<endl; for(int i=1;i<=s;i++){ cout<<c[i]<<" "; } }加粗文本

BT......

T1【区间动态规划】石子合并问题I T2【区间动态规划】石子合并问题II T3【区间动态规划】能量项链 T4【区间动态规划】回文子串

（例）

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这里是一个专属于柯迷的小空间，这里没有作业。想加入的连接在这https://www.acgo.cn/application/1872598016465047552。

最近被老壁灯盗号了，可能影响了大家，有影响跟我说~~