T19368.邻居 题解
2024-08-07 14:31:48
发布于:广东
不会有人不会吧
#include<iostream>
using namespace std;
int main(){
int n,m,y,x;
cin>>n>>m>>y>>x;
if(x+1>=m)cout<<"NA"<<endl;
else cout<<y<<" "<<x+1<<endl;
if(y+1>=n)cout<<"NA"<<endl;
else cout<<y+1<<" "<<x<<endl;
if(x-1<=0)cout<<"NA"<<endl;
else cout<<y<<" "<<x-1<<endl;
if(y-1<=0)cout<<"NA"<<endl;
else cout<<y-1<<" "<<x<<endl;
return 0;
}
这里空空如也
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