题解（不是抄的）

因为1+2+4+……+2^n = 2^n - 1，所以我们可以先将n+1
代码

#include <iostream>
#include <cstdio>
using namespace std;
long long n;
int main(){
	int ct = -1;
	cin >> n;
	n++;
	for(long long i = 1; i <= n; i *= 2){
		ct++;
	}
	cout << ct << endl;
	for( long long i = 2; i <= n; i *= 2){
		cout << i / 2 << endl;
	}
	return 0;
}